Have hammer, recognise screw, without screwdriver

by Kofi Sarfo 1. February 2010 06:14

For all it's usefulness XQuery never really took off the way it seems it should have done. We have a query language from the W3C for XML and since XML use is pervasive... it's very much like SQL which is wildly popular and since querying data is a fairly natural thing to want to do... and there are some excellent tools from Altova, Stylus Studio and Saxonica... However, there the story appears to end without the expected outcome. Going forward (sorry) we'll certainly be making greater use of XQuery because so many of the terabytes we process are wrapped in angle brackets and it's XML all the way down to even input & output parameters on stored procedures.

To demonstrate its value by example. Here's one way to generate XML using LINQ and hash table to validate against a given schema:

using System.Collections.Generic; using System.Linq; using System.Xml.Linq; namespace Wimiro.Data.Examples { public static class TransformXmlImperatively { public static string GenerateCdsSpreadOutput(this string xml, string requestXml) { var rootNode = xml.GetXmlDocument().FirstChild; var xmlWithNewDocumentRoot = rootNode.GetProcessingInstruction(); xmlWithNewDocumentRoot += "<" + requestXml.GetResponseRootElementName() + " xsi:noNamespaceSchemaLocation=\"curves.xsd\" " + " xmlns:xsi=\"http://www.w3.org/2001/XMLSchema-instance\">"; xmlWithNewDocumentRoot += xml.GetCurvesPointsFromXml(); xmlWithNewDocumentRoot += "</" + requestXml.GetResponseRootElementName() + ">"; return xmlWithNewDocumentRoot; } public static string GetCurvesPointsFromXml(this string xml) { var curveDictionary = new Dictionary<string, XElement>(); var rawDoc = XDocument.Parse(xml); var rawElements = from elements in rawDoc.Elements("root").Elements("row") select elements; var curveRoot = new XDocument(new XElement("root")); foreach (var rawElement in rawElements) { if (!ContainsCurve(curveDictionary, rawElement)) { AddCurve(curveDictionary, rawElement, curveRoot); } FindCurve(curveDictionary, rawElement).Add(GetCurvePoint(rawElement)); } return curveRoot.ToXml().StripRoot(); } private static XElement FindCurve(IDictionary<string, XElement> curveDictionary, XElement rawElement) { return curveDictionary[rawElement.GetKey()]; } private static XElement GetCurvePoint(XElement rawElement) { XElement curvePoint; curvePoint = new XElement("Point"); curvePoint.SetAttributeValue("Spread", rawElement.Attribute("Spread").Value); curvePoint.SetAttributeValue("Maturity", rawElement.Attribute("Maturity").Value); return curvePoint; } private static void AddCurve(Dictionary<string, XElement> curveDictionary, XElement rawElement, XDocument curveRoot) { XElement curveElement; curveElement = new XElement("Curve"); curveRoot.Element("root").Add(curveElement); curveDictionary.Add(rawElement.GetKey(), curveElement); foreach (var curveAttribute in rawElement.Attributes()) curveElement.SetAttributeValue(curveAttribute.Name, curveAttribute.Value); curveElement.SetAttributeValue("Spread", null); curveElement.SetAttributeValue("Maturity", null); } private static bool ContainsCurve(IDictionary<string, XElement> curveDictionary, XElement rawElement) { return curveDictionary.ContainsKey(rawElement.GetKey()); } } }

And here's the way it should have been done using XQuery:

select @xml_out.query (' for $Ticker in distinct-values(/root/row/@Ticker) let $Tickers := /root/row[@Ticker=$Ticker] for $Currency in distinct-values($Tickers/@Currency) let $Currencies := $Tickers[@Currency=$Currency] for $Date in distinct-values($Currencies/@Date) let $Dates := $Currencies[@Date=$Date] return <Curve Ticker="{$Ticker}" Currency="{$Currency}" Date="{$Date}">{ for $node in $Dates return <Point Maturity="{data($node/@Maturity)}" Spread="{data($node/@Spread)}" /> } </Curve>')

StackOverflow! For all your hardware needs.

Kiva Loans

  • Solangel Del Carmen

    Solangel Del Carmen

    Sewing

    Requested loan: $875

    Amount raised: $0

    Jipijapa, Ecuador

    to buy fabric, thread and other materials for dressmaking.

    Loan Now »

  • Benigna Nelly

    Benigna Nelly

    Poultry

    Requested loan: $975

    Amount raised: $0

    Jipijapa, Ecuador

    to buy chickens.

    Loan Now »

  • Tigidankay

    Tigidankay

    Food Market

    Requested loan: $175

    Amount raised: $0

    Wilberforce, Sierra Leone

    to purchase more foodstuffs and other assorted items to increase her business.

    Loan Now »

To see more entrepreneurs »

Make a loan to an entrepreneur across the globe for as little as $25. Kiva is the world's first online lending platform connecting online lenders to entrepreneurs across the globe.